k+2k+3k+3k+k^2+2k^2+7k^2+K=1

Solution for k+2k+3k+3k+k^2+2k^2+7k^2+K=1 equation:

k+2k+3k+3k+k^2+2k^2+7k^2+=1

We move all terms to the left:

k+2k+3k+3k+k^2+2k^2+7k^2+-(1)=0

determiningTheFunctionDomain
k^2+2k^2+7k^2+k+2k+3k+3k-1+=0

We add all the numbers together, and all the variables

10k^2+9k=0

a = 10; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·10·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*10}=\frac{-18}{20}
=-9/10
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*10}=\frac{0}{20}
=0
$